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Question

The value of tanπ16+2tanπ8+4 is equal to

A
cotπ8
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B
cotπ16
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C
cotπ1614
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D
none of these
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Solution

The correct option is D cotπ16
Weknowthat,tanA=cotA2cot2ALHS=tanπ16+2tanπ8+4=cotπ162cotπ8+2(cotπ82cotπ4)+4=cotπ16+44=cotπ16

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