The value of tan-tan90- is equal to

The correct option is D 1 tanθ·tan(90 θ) #160;= tanθ×θ #160;= 1 #160; #160; ∵ #160;tan(90 θ) =θ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Range of Trigonometric Ratios from 0 to 90 Degrees

The value of ...

Question

The value of $tan θ \cdot tan (90 - θ)$ is equal to

{sin}^{2} θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{cos}^{2} θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

θ

\frac{π}{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {sin}^{2} θ & {cos}^{2} θ & 4 sin 4 θ {sin}^{2} θ & 1 + {cos}^{2} θ & 4 sin 4 θ {sin}^{2} θ & {cos}^{2} θ & 1 + 4 sin 4 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

tan θ \cdot tan (90 - θ)

[{sin}^{2} θ \int 0 {sin}^{- 1} \sqrt{ϕ} d ϕ + {cos}^{2} θ \int 0 {cos}^{- 1} \sqrt{ϕ} d ϕ]

s i n^{2} θ - c o s^{2} θ

\sqrt{3} \tan θ = 3 \sin θ, find the value of \sin^{2} θ - \cos^{2} θ, w h e r e θ \neq 0 .

Join BYJU'S Learning Program