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Question

The value of tan58 tan32 tan57 tan33 is


A

2

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B

3

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C

1

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D

0

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Solution

The correct option is C

1


tan32=tan(9058)
=cot58

tan33=tan(9057)
=cot57

Therefore,
tan58 tan32 tan57 tan33
= tan58 cot58 tan57 cot57
= tan58 1tan58tan571tan57
[since cot A=1tanA]
=1


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