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Question

The value of cosecθ+sec(270°θ)cosec(270°+θ)+sec(180°θ) is

A
0
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B
1
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C
2(secθ+cosecθ)
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D
2secθ
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Solution

The correct option is A 0
cosecθ+sec(270°θ)cosec(270°+θ)+sec(180°θ)

=cosecθcosecθ+secθsecθ

=0

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