The value of ∫3−2|1−x2|dx is pq in it's simplest form. Then what p+q is ___
∫3−2|1−x2|dx=∫−1−2(x2−1)dx+∫1−1(1−x2)dx+∫31(x2−1)dx =[x33−x]−1−2+[x−x33]1−1+[x33−x]31 =43+43+203=283
pq=283
p=28,q=3
p+q=31
We are given a set of first 100 naturals numbers. If the probability of the product of two numbers selected from this set be divisible by 7 is given by pq in it's simplest form. Then p+q+1p−9 is ___