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Question

The value of 32|1x2|dx is pq in it's simplest form. Then what p+q is ___

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Solution

32|1x2|dx=12(x21)dx+11(1x2)dx+31(x21)dx
=[x33x]12+[xx33]11+[x33x]31
=43+43+203=283

pq=283

p=28,q=3

p+q=31


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