The value of - for which 2 cos 2-sin-2-0-0- 90- is-

The correct option is C 30° ...

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Complementary Trigonometric Ratios

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Question

The value of θ for which 2cos²θ + sinθ - 2 = 0. 0^o < θ ≤90^o is:

30°

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10°

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60°

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45°

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\frac{\cos^{4} θ + \cos^{2} θ \sin^{2} θ + \sin^{2} θ}{\cos^{2} θ + \cos^{2} θ \sin^{2} θ + \sin^{4} θ}

θ

s i n^{2} θ + c o s^{2} θ =

θ

{cos}^{2} (cos θ) + {sin}^{2} (sin θ)

θ \in (0, \frac{π}{3})

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {cos}^{2} θ & {sin}^{2} θ & 4 cos 6 θ {cos}^{2} θ & 1 + {sin}^{2} θ & 4 cos 6 θ {cos}^{2} θ & {sin}^{2} θ & 1 + 4 cos 6 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0 is :

{sin}^{2} θ_{1} + {sin}^{2} θ_{2} + {sin}^{2} θ_{3} = 0

{cos}^{2} θ_{1} + {cos}^{2} θ_{2} + {cos}^{2} θ_{3}

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