Question

The value of the assets distributed among Neeta, Seeta and Geeta was in the ratio of 1:2:3, while the gold coins were distributed among them in the ratio of 2:3:4. One child got all three flats and she did not get the house. One child, other than Geeta, got Rs. 30 lakh in bank deposits.
How many gold coins did the old woman have?

• A. 72
• B. 90
• C. 180
• D. 216

Answer 1

The correct option is B

90

Refer to the table given below:
$\begin{array}{cccc}\text{Asset}& \text{Neeta}& \text{Seeta}& \text{Geeta}\\ \text{Flats (Rs.in lakhs)}& & & 30+30+30=90\\ \text{House (Rs.in lakhs)}& & 50& \\ \text{Bank deposits(Rs. in lakhs)}& 30& x_2& x_3\\ \text{Coins (Total number=n and)}& 2n& 3n& 4n\\ \text{Total value=n}\times \text{1=Rs.n lakhs)}& & & \\ \text{Total (Rs. in lakhs)}& 30+2n& 50+x_2+3n& 90+x_3+4n\end{array}$
Given, $90+x_3+4n=3(30+2n)$
$x_3=2n-------\left(1\right)$
& $50+x_2+3n=2(30+2n)$
$x_2-n=10---------\left(2\right)$
Solving 1) & 2), we get
$2x_2-x_3=20-------\left(3\right)$
But we know that $x_2+x_3=70-30=40------\left(4\right)$
Solving (3) & (4), we get
$x_2=x_3$ = Rs. 20 lakhs
Putting the value of $x_2$ in (2), we get
n = 10
Hence, the number of gold coins with the old lady is $9n=9\times 10=90$.