The value of the derivative of the function y -16 x 3 at x -1 isA- -1B- -16C- -48D- 48

The correct option is D 48dydx nbsp;= nbsp;48x2 Putting x = 1, y = 48 ...

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Basic Differentiation Rule

The value of ...

Question

The value of the derivative of the function $y = 16 x^{3} a t x = - 1$ is

-1

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-16

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-48

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Similar questions

y = 16 x^{3} a t x = - 1

y = 16 x^{3} + 16 x^{2} a t x = - 1

f (x) = ⎧ ⎨ ⎩ \begin{matrix} \frac{2 - x^{2} - 2 cos x}{2 x^{4}} for x \neq 0 k for x = 0 \end{matrix}

x = 0

k

y = f (x)

f^{''} (x) = 6 (x - 1)

(2, 1)

y = 3 x - 5

f (0)

c o s^{- 1} (\frac{x^{- 1} - x}{x^{- 1} + x}) a t x = - 1

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