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Byju's Answer
Standard X
Mathematics
Solving a Quadratic Equation by Factorization Method
The value of ...
Question
The value of the determinant
∆
=
1
2
3
4
5
6
3
x
6
x
9
x
is ____________.
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Solution
Given:
∆
=
1
2
3
4
5
6
3
x
6
x
9
x
∆
=
1
2
3
4
5
6
3
x
6
x
9
x
Taking
3
x
common
from
R
3
⇒
∆
=
3
x
1
2
3
4
5
6
1
2
3
⇒
∆
=
3
x
0
∵
The
value
of
determinant
with
two
identicals
rows
is
equal
to
zero
⇒
∆
=
0
Hence, the value of the determinant
∆
=
1
2
3
4
5
6
3
x
6
x
9
x
is
0
.
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0
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