Question

The value of the determinant $\left(\begin{array}{ccc}1& 2& 4\\ -1& 3& 0\\ 4& 1& 0\end{array}\right|$ will be .

• A. -13
• B. -52
• C. \N
• D. -4

Answer 1

The correct option is B -52

Here, in the third column two elements are zero. So, expanding along the third column we get:
$\Delta =4\left(\begin{array}{cc}-1& 3\\ 4& 1\end{array}\right|-0\left(\begin{array}{cc}1& 2\\ 4& 1\end{array}\right|+0\left(\begin{array}{cc}1& 2\\ -1& 3\end{array}\right|=4(-1-12)-0+0=-52$