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Question

The value of the determinant ∣ ∣ ∣1aa2cos(n1)xcosnxcos(n+1)xsin(n1)xsinnxsin(n+1)x∣ ∣ ∣ is zero if

A
x=nπ
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B
x=nπ/2
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C
x=(2n+1)π/2
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D
x=1+a22anεI
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Solution

The correct option is A x=nπ
∣ ∣ ∣1aa2cos(n1)xcosnxcos(n+1)xsin(n1)xsinnxsin(n+1)x∣ ∣ ∣=0
C1C22cosxC2+C3
∣ ∣ ∣12acosx+a2aa20cosnxcos(n+1)x0sinnxsin(n+1)x∣ ∣ ∣
(12acosx+a2)sinx=0
sinx=0orcosx=(1+a2)2a
x=nπ,nI.

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