MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Evaluation of a Determinant

The value of ...

Question

The value of the determinant $∣ ∣ ∣ ∣ \begin{matrix} 4 & - 6 & 1 - 1 & - 1 & 1 - 4 & 11 & - 1 \end{matrix} ∣ ∣ ∣ ∣$ is

A

-75

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

-25

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D -25
$∣ ∣ ∣ ∣ \begin{matrix} 4 & - 6 & 1 - 1 & - 1 & 1 - 4 & 11 & - 1 \end{matrix} ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ \begin{matrix} 0 & 5 & 0 - 1 & - 1 & 1 - 4 & 11 & - 1 \end{matrix} ∣ ∣ ∣ ∣ {A p p l i n g R_{1} \to R_{1} + R_{3}} = - 5 (1 + 4) = - 25$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. The value of the determinant

∣ ∣ ∣ ∣ \begin{matrix} 4 & - 6 & 1 - 1 & - 1 & 1 - 4 & 11 & - 1 \end{matrix} ∣ ∣ ∣ ∣

Q. The value of the determinant

∣ ∣ ∣ ∣ \begin{matrix} 4 & - 6 & 1 - 1 & - 1 & 1 - 4 & 11 & - 1 \end{matrix} ∣ ∣ ∣ ∣

Q. Find the value of the determinant.

A = ∣ ∣ ∣ \begin{matrix} 3 & - 1 - 5 & 4 \end{matrix} ∣ ∣ ∣ =

\frac{\frac{1}{2} + 3 \frac{1}{4} + 1 \frac{1}{6}}{2 \frac{1}{2} + 1 \frac{1}{6} + 6 \frac{1}{3}} + \frac{1}{120}

Q. lf the value of a third order determinant is 11, then the value of the determinant of

A^{- 1} =

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Evaluation of Determinants

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Evaluation of a Determinant

Standard XIII Mathematics

Join BYJU'S Learning Program

CrossIcon