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Byju's Answer
Standard XII
Mathematics
Evaluation of a Determinant
The value of ...
Question
The value of the determinant
∣
∣ ∣
∣
4
−
6
1
−
1
−
1
1
−
4
11
−
1
∣
∣ ∣
∣
is
A
-75
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B
25
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C
\N
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D
-25
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Solution
The correct option is
D
-25
∣
∣ ∣
∣
4
−
6
1
−
1
−
1
1
−
4
11
−
1
∣
∣ ∣
∣
=
∣
∣ ∣
∣
0
5
0
−
1
−
1
1
−
4
11
−
1
∣
∣ ∣
∣
{
A
p
p
l
i
n
g
R
1
→
R
1
+
R
3
}
=
−
5
(
1
+
4
)
=
−
25
.
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1
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