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Byju's Answer
Standard XII
Mathematics
Evaluation of a Determinant
The value of ...
Question
The value of the determinant
∣
∣ ∣
∣
a
b
c
a
2
b
2
c
2
b
c
c
a
a
b
∣
∣ ∣
∣
is
A
a
b
c
(
a
b
)
(
b
c
)
(
c
a
)
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B
(
a
+
b
)
(
b
c
)
(
c
a
)
(
a
+
b
+
c
)
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C
(
a
b
)
(
b
c
)
(
c
a
)
(
a
b
+
b
c
+
c
a
)
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D
none
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Solution
The correct option is
D
none
∣
∣ ∣ ∣
∣
a
b
c
a
2
b
2
c
2
b
c
c
a
a
b
∣
∣ ∣ ∣
∣
a
(
b
3
a
−
c
3
a
)
−
b
(
a
3
b
−
c
3
b
)
+
c
(
a
3
c
−
b
3
c
)
⇒
a
2
b
3
−
a
2
c
3
−
a
3
b
2
+
c
3
b
2
+
a
3
c
2
−
b
3
c
2
⇒
a
2
b
2
(
b
−
a
)
+
a
2
c
2
(
a
−
c
)
+
b
2
c
2
(
c
−
b
)
Option D-none
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0
Similar questions
Q.
The value of the determinant
∣
∣ ∣ ∣
∣
1
a
a
2
−
b
c
1
b
b
2
−
c
a
1
c
c
2
−
a
b
∣
∣ ∣ ∣
∣
is
Q.
Find the value of determinant,
∣
∣ ∣ ∣
∣
1
a
a
2
−
b
c
1
b
b
2
−
c
a
1
c
c
2
−
a
b
∣
∣ ∣ ∣
∣
Q.
If
a
,
b
,
c
are roots of the equation
A
x
3
+
B
x
2
+
C
=
0
then the value of determinant
∣
∣ ∣
∣
a
b
b
c
c
a
b
c
c
a
a
b
c
a
a
b
b
c
∣
∣ ∣
∣
equals to=?
Q.
Show that the determinant
∣
∣ ∣ ∣
∣
a
2
+
b
2
+
c
2
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
a
2
+
b
2
+
c
2
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
a
2
+
b
2
+
c
2
∣
∣ ∣ ∣
∣
is always non-negative.
Q.
The value of the determinant
∣
∣ ∣ ∣
∣
1
a
a
2
−
b
c
1
b
b
2
−
c
a
1
c
c
2
−
a
b
∣
∣ ∣ ∣
∣
is .....................
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