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Question

The value of the determinant ∣∣ ∣ ∣∣(ax+a−x)2(ax−a−x)21(bx+b−x)2(bx−b−x)21(cx+c−x)2(cx−c−x)21∣∣ ∣ ∣∣ is

A
0
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B
2abc
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C
a2b2c2
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D
None of these
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Solution

The correct option is D 0
Given determinant is

=∣ ∣ ∣(ax+ax)2(axax)21(bx+bx)2(bxbx)21(cx+cx)2(cxcx)21∣ ∣ ∣

Applying C1C1C2, we get

=∣ ∣ ∣4(axax)214(bxbx)214(cxcx)21∣ ∣ ∣

=4∣ ∣ ∣1(axax)211(bxbx)211(cxcx)21∣ ∣ ∣

=0 ( two columns are identical).

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