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Byju's Answer
Standard XII
Mathematics
Addition and Subtraction of a Matrix
The value of ...
Question
The value of the determinant
∣
∣ ∣ ∣
∣
b
2
−
a
b
b
−
c
b
c
−
a
c
a
b
−
a
2
a
−
b
b
2
−
a
b
b
c
−
a
c
c
−
a
a
b
−
a
2
∣
∣ ∣ ∣
∣
A
a
b
c
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B
a
+
b
+
c
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C
0
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D
a
b
+
b
c
+
c
a
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Solution
The correct option is
C
0
∣
∣ ∣ ∣
∣
b
2
−
a
b
b
−
c
b
c
−
a
c
a
b
−
a
2
a
−
b
b
2
−
a
b
b
c
−
a
c
c
−
a
a
b
−
a
2
∣
∣ ∣ ∣
∣
=
∣
∣ ∣ ∣
∣
(
b
−
a
)
b
b
−
c
(
b
−
a
)
c
(
b
−
a
)
a
a
−
b
(
b
−
a
)
b
(
b
−
a
)
c
c
−
a
(
b
−
a
)
a
∣
∣ ∣ ∣
∣
=
(
b
−
a
)
2
∣
∣ ∣
∣
b
b
−
c
c
a
a
−
b
b
c
c
−
a
a
∣
∣ ∣
∣
=
(
b
−
a
)
2
∣
∣ ∣
∣
b
b
c
a
a
b
c
c
a
∣
∣ ∣
∣
−
(
b
−
a
)
2
∣
∣ ∣
∣
b
c
c
a
b
b
c
a
a
∣
∣ ∣
∣
=
0
+
0
=
0
since two columns in each determinant are identical.
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Similar questions
Q.
The value of the determination
∣
∣ ∣ ∣
∣
b
2
−
a
b
b
−
c
b
c
−
a
c
a
b
−
a
2
a
−
b
b
2
−
a
b
b
c
−
a
c
c
−
a
a
b
−
a
2
∣
∣ ∣ ∣
∣
=
Q.
∣
∣ ∣ ∣
∣
b
2
−
a
b
b
−
c
b
c
−
a
c
a
b
−
a
2
a
−
b
b
2
−
a
b
b
c
−
a
c
c
−
a
a
b
−
a
2
∣
∣ ∣ ∣
∣
=
Q.
The determinant
b
2
-
a
b
b
-
c
b
c
-
a
c
a
b
-
a
2
a
-
b
b
2
-
a
b
b
c
-
c
a
c
-
a
a
b
-
a
2
equals
(a)
a
b
c
b
-
c
c
-
a
a
-
b
(b)
b
-
c
c
-
a
a
-
b
(c)
a
+
b
+
c
b
-
c
c
-
a
a
-
b
(d) none of these
Q.
Find the value of the determinant without expansion
∣
∣ ∣ ∣
∣
b
2
−
a
b
b
−
c
b
c
−
a
c
a
b
−
a
2
a
−
b
b
2
−
a
b
b
c
−
a
c
c
−
a
a
b
−
a
2
∣
∣ ∣ ∣
∣
Q.
Show that the determinant
∣
∣ ∣ ∣
∣
a
2
+
b
2
+
c
2
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
a
2
+
b
2
+
c
2
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
b
c
+
c
a
+
a
b
a
2
+
b
2
+
c
2
∣
∣ ∣ ∣
∣
is always non-negative.
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