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Byju's Answer
Standard XII
Mathematics
Properties of Determinants
The value of ...
Question
The value of the determinant
∣
∣ ∣ ∣
∣
1
m
C
1
m
C
21
1
m
+
1
C
1
m
+
1
C
2
1
m
+
2
C
1
m
+
2
C
2
∣
∣ ∣ ∣
∣
is equal to
A
1
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B
−
1
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C
0
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D
None of these
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Solution
The correct option is
A
1
There are some properties to find the determinant without expanding them, they are :
⇒
If a matrix has all the elements zero in any row or column, then value of its determinant is zero
⇒
If a matrix has any two rows or columns identical, then the value of its determinant is zero
⇒
by substituting
C
1
=
C
1
+
C
2
+
C
3
if it gives the C1 as 0
then the value of its determinant is zero.
here these three points are not satisfied hence the
determinant
is
1
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0
Similar questions
Q.
The value of the determinant
∣
∣ ∣ ∣
∣
1
1
1
m
C
1
m
+
1
C
1
m
+
2
C
1
m
C
2
m
+
1
C
2
m
+
2
C
2
∣
∣ ∣ ∣
∣
is equal to
Q.
∣
∣ ∣ ∣
∣
1
1
1
m
C
1
m
+
1
C
1
m
+
2
C
1
m
C
2
m
+
1
C
2
m
+
2
C
2
∣
∣ ∣ ∣
∣
=
1
Given
m
ϵ
N
m
≥
2
Q.
If
(
1
+
x
)
n
=
C
0
+
C
1
x
+
C
2
x
2
+
⋯
+
C
n
x
n
,
n
∈
N
,
then for
2
≤
m
≤
n
,
C
0
−
C
1
+
C
2
−
⋯
+
[
(
−
1
)
m
−
1
]
C
m
−
1
is equal to
Q.
There are two numbers x making the value of the determinant
∣
∣ ∣
∣
1
−
2
5
2
x
−
1
0
4
2
x
∣
∣ ∣
∣
equal to
86
. The sum of these two numbers, is?
Q.
If a,b,c are in H.P., then the value of
(
1
b
+
1
c
−
1
a
)
(
1
c
+
1
a
−
1
b
)
, is
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