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Question

The value of the determinant
∣ ∣ ∣1mC1mC211m+1C1m+1C21m+2C1m+2C2∣ ∣ ∣ is equal to

A
1
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B
1
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C
0
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D
None of these
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Solution

The correct option is A 1
There are some properties to find the determinant without expanding them, they are :

If a matrix has all the elements zero in any row or column, then value of its determinant is zero

If a matrix has any two rows or columns identical, then the value of its determinant is zero

by substituting C1=C1+C2+C3 if it gives the C1 as 0 then the value of its determinant is zero.

here these three points are not satisfied hence the determinant is 1

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