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Question

The value of determinant sinαcosαsin(α+γ)sinβcosβsin(β+γ)sinδcosδsin(γ+δ) is


A

sinα.sinβ.sinδ

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B

cosα.cosβ.cosδ

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C

1

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D

0

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Solution

The correct option is D

0


Explanation for correct option:
Given sinαcosαsin(α+γ)sinβcosβsin(β+γ)sinδcosδsin(γ+δ)
sinαcosαsin(α+γ)sinβcosβsin(β+γ)sinδcosδsin(γ+δ)=sinαcosαsinαcosγ+cosαsinγsinβcosβsinβcosγ+cosβsinγsinδcosδsinγcosδ+cosγsinδ[sin(a+b)=sin(a)cos(b)+cos(a)sin(b)]
=sinαcosαsinαcosγsinβcosβsinβcosγsinδcosδcosγsinδ+sinαcosαcosαsinγsinβcosβcosβsinγsinδcosδsinγcosδ=cosγsinαcosαsinαsinβcosβsinβsinδcosδsinδ+sinγsinαcosαcosαsinβcosβcosβsinδcosδcosδ
=cosγ×0+sinγ×0 [if two columns are same then the determinant is equal to zero]
=0

Hence option(D) is correct


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