1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XIII
Mathematics
Evaluation of a Determinant
The value of ...
Question
The value of the determinat
(
cos
θ
−
sin
θ
sin
θ
cos
θ
∣
∣
∣
is
.
A
2
sin
2
θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
cos
2
θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is
D
1
(
cos
θ
−
sin
θ
sin
θ
cos
θ
∣
∣
∣
=
cos
θ
(
cos
θ
)
−
sin
θ
(
−
sin
θ
)
=
cos
2
θ
+
sin
2
θ
=
1
Suggest Corrections
0
Similar questions
Q.
If
c
o
s
θ
+
s
i
n
θ
=
√
c
o
s
θ
, then what is the value of
c
o
s
θ
−
s
i
n
θ
? [3 MARKS]
Q.
Prove that the determinant
∣
∣ ∣
∣
x
s
i
n
θ
c
o
s
θ
−
s
i
n
θ
−
x
1
c
o
s
θ
1
x
∣
∣ ∣
∣
is independent of
θ
.
Q.
The value of the determinant
sin
A
cos
A
sin
A
+
cos
B
sin
B
cos
A
sin
B
+
cos
B
sin
C
cos
A
sin
C
+
cos
B
is ________________.
Q.
If \,
θ
lies in 4th quadrant and
sin
θ
2
+
cos
θ
2
=
−
1
2
Then determine the value of
sin
2
θ
Q.
The equation
(
2
c
o
s
θ
+
3
s
i
n
θ
)
x
+
(
3
c
o
s
θ
−
5
s
i
n
θ
)
y
−
(
5
c
o
s
θ
−
2
s
i
n
θ
)
=
0
pass through a fixed point for all values of
θ
.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Evaluation of Determinants
MATHEMATICS
Watch in App
Explore more
Evaluation of a Determinant
Standard XIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app