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Question

The value of the expression 1−sin2y1+cos y+1+cos ysin y−sin y1−cos y


A

0

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B

1

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C

sin y

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D

cos y

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Solution

The correct option is D

cos y


11cos2y1+cosy+(1cos2y)sin2ysiny(1+cosy)=1(1cosy)+0=cosy


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