The value of the expression 2log 3-1-2log 16-log 12 is equal to

The correct option is B log 27 2log 3 1/2log 16+log 12 =log 3^2 log 16^1/2+log 12 nbsp; nbsp;[using power law] =log 9 log 4+log 12 =log (9×12) log 4 nbs ...

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Standard X

Mathematics

Properties of Logarithms

The value of ...

Question

The value of the expression $2 l o g 3 - \frac{1}{2} l o g 16 + l o g 12$ is equal to ___

$l o g 13$

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$l o g 27$

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$l o g 72$

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$l o g 36$

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Solution

The correct option is B
$l o g 27$

$2 l o g 3 - \frac{1}{2} l o g 16 + l o g 12$

$= l o g 3^{2} - l o g 16^{1 / 2} + l o g 12$ [using power law]

$= l o g 9 - l o g 4 + l o g 12$

$= l o g (9 \times 12) - l o g 4$ [using product law]

$= l o g \frac{108}{4}$ [using quotient law]

$= l o g 27$

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[Karnataka CET 1999]

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The value of the expression 2log 3−12log 16+log 12 is equal to ___

The correct option is B log 27 2log 3−12log 16+log 12 =log 32−log 161/2+log 12 [using power law] =log 9−log 4+log 12 =log (9×12)−log 4 [using product law] =log 1084 [using quotient law] =log 27

The value of the expression $2 l o g 3 - \frac{1}{2} l o g 16 + l o g 12$ is equal to ___

The correct option is B
$l o g 27$

$2 l o g 3 - \frac{1}{2} l o g 16 + l o g 12$

$= l o g 3^{2} - l o g 16^{1 / 2} + l o g 12$ [using power law]

$= l o g 9 - l o g 4 + l o g 12$

$= l o g (9 \times 12) - l o g 4$ [using product law]

$= l o g \frac{108}{4}$ [using quotient law]

$= l o g 27$