The correct options are
A 0 if n is odd
C (−1)n2 nCn2 if n is even
When n is odd, taken n = 2m + 1, so that
S=C20−C21+C22−⋯+(−1)2mC22m+(−1)2m+1C22m+1
=(C20−C22m+1)−(C21−C22m)+⋯
But 2m+1C0=2m+1C2m+1,
2m+1C1= 2m+1C2m etc.
Therefore S = 0
When n is even, we take n = 2m. In this case
C20−C21+C22−C23+⋯+(−1)2mC22m
= Coefficient of constant term in
[C0−C1x+C2x2−⋯+(−1)2mC2mx2m]
[C0+C11x+c21x2+⋯+C2m1x2m]
= Coefficient of constant term in
(1−x)2m(1+1x)2m
= Coefficient of x2m in (1−x)2m(1+x)2m
= Coefficient of x2m in (1−x2)2m
=(−1)m(2mCm)=(−1)n2(nCn2)