Question

The value of the expression $\frac{8!}{(6-2)!\times 2!}$ is

Answer 1

$\underset{–}{\text{Need to Find}:}$
The value of $\frac{8!}{(6-2)!\times 2!}$
$\frac{8!}{(6-2)!\times 2!}$

$=\frac{8!}{4!\times 2!}$

$=\frac{8\times 7\times 6\times 5\times 4!}{(4!)\times (2\times 1)}$

$=\frac{8\times 7\times 6\times 5}{(2\times 1)}$

$=\frac{4\times 2\times 7\times 6\times 5}{2}$ $(\because 8=4\times 2)$

$=4\times 7\times 6\times 5=840$

Therefore, the value of given expression $\frac{8!}{(6-2)!\times 2!}$ is $840.$