wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of the expression tan2200sin2200tan2200.sin2200 is

A
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1
Given expression is tan2200sin2200tan2200.sin2200

We know that, tanθ=sinθcosθ

Hence, tan2θ=sin2θcos2θ

tan2200sin2200tan2200.sin2200=sin2200cos2200sin2200sin2200cos2200sin2200
=sin2200sin2200cos2200sin4200

=sin2200(1cos2200)sin4200
We also know that, sin2θ+cos2θ=1
Hence, 1cos2θ=sin2θ
So, sin2200sin2200sin4200

=sin4200sin4200

=1

Hence, tan2200sin2200tan2200.sin2200=1.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon