The correct option is A 15
10× 10× 10+5× 5× 5 can be written as 103+53.
Also, 10× 10−10× 5+5× 5 can be written as (102−10× 5+52)
Using the identity (a3+b3)=(a+b)(a2−ab+b2),
we can say that 103−53102−10× 5+52=(10+5)(102−10× 5+52)102−10× 5+52=(10+5)=15