CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of the expression (ω1)(ωω2)(ωω3)...(ωωn1), where ω is the nth root of unity, is

A
nωn1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
nωn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(n1)ωn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(n1)ωn1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A nωn1
We have, xn1=(x1)(xω)(xω2)...(xωn1)

xn1xω=(x1)(xω2)...(xωn1)

Putting x=ω on both sides, we have

(ω1)(ωω2)...(ωωn1)=limxωxn1xω(00form)

=limxωnxn11=nωn1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inverse of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon