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Question

The value of the expression (ω1)(ωω2)(ωω3)...(ωωn1), where ω is the nth root of unity, is

A
nωn1
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B
nωn
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C
(n1)ωn
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D
(n1)ωn1
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Solution

The correct option is A nωn1
We have, xn1=(x1)(xω)(xω2)...(xωn1)

xn1xω=(x1)(xω2)...(xωn1)

Putting x=ω on both sides, we have

(ω1)(ωω2)...(ωωn1)=limxωxn1xω(00form)

=limxωnxn11=nωn1

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