The value of the expression ${tan}^{6} 20^{0} - 33 {tan}^{4} 20^{0} + 27 {tan}^{2} 20^{0}$ is

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Solution

The correct option is D $3$
$tan 60^{\circ} = \frac{3 tan 20^{\circ} - {tan}^{3} 20^{\circ}}{1 - 3 tan 20^{\circ}} = \sqrt{3}$
we not square both sides to get the result

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