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Algebraic Identity: (x + y)(x - y)

The value of ...

Question

The value of the expression $(x + y) (x - y)$ would be equal to $x^{2} - y^{2}$ .

A

True

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B

False

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Solution

The correct option is A True

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Similar questions

x^{y} = y^{x},

(\frac{x}{y})^{\frac{x}{y}}

is equal to:

b) If

\frac{x}{y} = \frac{6}{5}

\frac{x^{2} + y^{2}}{x^{2} - y^{2}}

x = 1; y = 2

, find the value of the following expression.

x^{2} + y^{2}

x^{y} = y^{x},

(\frac{x}{y})^{\frac{x}{y}}

is equal to:

b) If

\frac{x}{y} = \frac{6}{5}

\frac{x^{2} + y^{2}}{x^{2} - y^{2}}

(x, y)

x^{2} + y^{2} - 4 x + 2 y + 1 = 0

then the expression

x^{2} + y^{2} - 10 x - 6 y + 34

cannot be equal to

Q. Assertion :Let a solution

y = y (x)

of the differential equation

x \sqrt{x^{2} - 1} d y - y \sqrt{y^{2} - 1} d x = 0

y (2) = 2 / \sqrt{3}

y (x) = sec ({sec}^{- 1} x - \frac{π}{6})

y (x)

\frac{1}{y} = \frac{2 \sqrt{3}}{x} - \sqrt{1 - \frac{1}{x^{2}}}

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