The value of the following polynomial at the indicate value of variables:
$q (y) = 3 y^{2} - 4 y + \sqrt{11}$ at $y = 2$ is equal to $4 + \sqrt{11}$ .

True

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False

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Solution

The correct option is A True
Given, $q (y) = 3 y^{2} - 4 y + \sqrt{11}$
Now, $q (2) = 3 (2)^{2} - 4 (2) + \sqrt{11}$
$= 12 - 8 + \sqrt{11}$
$= 4 + \sqrt{11}$

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Similar questions

q (y) = 3 y^{2} - 4 y \sqrt{11} + 8 \sqrt{11}

y = 2

q (y) = 2 y^{3} - 4 y + \sqrt{11}

y = 1. (\sqrt{11} = 3.32)

p (t) = 4 t^{4} + 5 t^{3} - t^{2} + 6

t = a

4 a^{4} + 5 a^{3} - a^{2} + 6

p (t) = 4 t^{4} + 5 t^{3} - t^{2} + 6

t = 0

p (x) = 5 x^{2} - 3 x + 7

x = 1

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