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Question

The value of the integral π01+cos2x2dx is

A
-2
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B
2
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C
0
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D
-3
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Solution

The correct option is B 2
π01+cos2x2dx=π0|cosx|dx
π/20cosx dxππ/2cosxdx
sinx π/20sinxππ/2
=1(1)
=2
Hence, option 'B' is correct.

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