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Question

The value of the integral
1/21/2cosx.log(1+x1x)dx is

A
0
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B
12
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C
12
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D
15
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Solution

The correct option is A 0

=1/21/2cosxlog(1+x1x)dx
I=1/21/2cos(x)log(1x1+x)dx
=1/21/2cosxlog(1x1+x)dx
2I=1/21/20dx
I=0


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