The value of the integral ∫63√x√9−x+√xdx is
I=∫63√x√9−x+√xdx ∫baf(x)dx=∫baf((a+b)−x)dx I=∫63√9−x√x+√9−xdx 2I=∫631⋅dx 2I=3 I=32
If 2|3x+9|<36, then the number of integral values of x is