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Question

The value of the integral dxxx2a2 is equal to :

A
c+1asin1a|x|
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B
c1asin1a|x|
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C
c1acos1a|x|
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D
sin1a|x|+c
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Solution

The correct option is B c1asin1a|x|
dxxx2a2=1asec1|x|a=1a(π2sin1a|x|)
=c1asin1a|x|, where c=π2a

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