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Question

The value of the integral
104[x2]dx[x228x+196]+[x2], where [x]
denotes the greatest integer less than or equal to x, is :

A
3
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B
7
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C
13
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D
6
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Solution

The correct option is A 3
I=104[x2]dx[x228x+196]+[x2]=104[x2]dx[(14x)2]+[x2]Using baf(a+bx)=baf(x)I=104[(14x)2]dx[(14x)2]+[x2]2I=104dx2I=104I=3

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