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Question

The value of the integral (x21)dxx3(2x42x2+1) is:

A
222x2+1x4+c
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B
22+2x2+1x4+c
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C
1222x2+1x4+c
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D
None of these
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Solution

The correct option is C 1222x2+1x4+c
I=(x21)dxx3(2x42x2+1)I=x21x522x2+1X4dxI=1x31x522x2+1X4dxPut 22x2+1X4=t(1x31x5)dx=dt4I=14dttI=12t+cI=1222x2+1x4+c

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