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Question

The value of the integral 0πcos(πx) will be equal to the value of which of the following integral.

A
π0cos(x)dx
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B
π0cos(x)dx
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C
π0sin(x)dx
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D
π0sin(x)dx
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Solution

The correct option is A π0cos(x)dx
This is only a two step problem if we understand the fact on interchanging the lower and upper limits adds a negative sign to the expression.
i.e., baf(x).dx=abf(x).dxSo here0πcos(πx)dx=0πcos(x)dx=π0cos(x)dx

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