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Question

The value of the limit limx0{11/sin2x+21/sin2x++n1/sin2x}sin2x is

A
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B
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C
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D
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Solution

The correct option is D
limx0{11sin2x+21sin2x++n1sin2x}sin2xPut 1sin2x=t1limt(1t+2t++nt)1t=limt(nt)1t[(1n)t+(2n)t++1]1t=nlimt[(1n)t+(2n)t++1]1t=n[0+0++1]0=n

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