wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of the limit limx0{11/sin2x+21/sin2x++n1/sin2x}sin2x is

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D
limx0{11sin2x+21sin2x++n1sin2x}sin2xPut 1sin2x=t1limt(1t+2t++nt)1t=limt(nt)1t[(1n)t+(2n)t++1]1t=nlimt[(1n)t+(2n)t++1]1t=n[0+0++1]0=n

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 4
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon