The value of the polynomial $5 x^{3} + 5 x^{2} + 4 x + 3$ when $x = - 1$ is

1

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- 1

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0

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None of the above

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Solution

The correct option is B $- 1$
$5 x^{2} + 5 x^{2} + 4 x + 3$
$= 5 \times (- 1)^{3} + 5 \times (- 1)^{2} - 4 + 3$
$= - 5 + 5 - 4 + 3$
$= - 1$

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Similar questions

The value of the polynomial $5 x^{3} - 4 x^{2} + 3$ when $x = - 1$ is

\frac{1}{2} x - 2 \sqrt{5} x^{2} + \frac{1}{\sqrt{5}} x^{3}

\frac{3}{2} x - 4 \sqrt{5} x^{2} + \frac{1}{\sqrt{5}} x^{3}

x - 2 \sqrt{5} x^{2}

5 x^{3} + M x + N

x^{2} + x + 1

M + N

\frac{1}{2} x - 2 \sqrt{5} x^{2} + \frac{1}{\sqrt{5}} x^{3}

\frac{3}{2} x - 4 \sqrt{5} x^{2} + \frac{1}{\sqrt{5}} x^{3}

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