The value of the polynomial $x^{2} - x - 1$ at $x = - 1$ is :

-3

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-1

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Solution

The correct option is B 1
$p (x) = x^{2} - x - 1$
Put $x = - 1$
$p (- 1) = (- 1)^{2} - (- 1) - 1$
$= 1 + 1 - 1 = 1$
So, $B$ is correct

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The value of polynomial p(x) = x³ – x² + x + 1 at x = 1 is

x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8

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