Question

The value of the product $(3+\frac{5}{x})$ and $(9-\frac{15}{x}+\frac{25}{x^2})$ at $x=1$ is _______.

• A. $150$
• B. $148$
• C. $152$
• D. $140$

Answer 1

The correct option is C $152$

The value of product $(3+\frac{5}{x})$ and $(9-\frac{15}{x}+\frac{25}{x^2})$ at $x=1$ be $f$

$(3+\frac{5}{x})$ at $x=1$ is equal to $3+\frac{5}{1}=3+5=8$

$(9-\frac{15}{x}+\frac{25}{x^2})$ at $x=1$ is equal to $9-\frac{15}{1}+\frac{25}{1}=9-15+25=19$

$y=8\times 19=152$ at $x=1$

Therefore, required product is $152$.

Option (C) is correct.