The value of the reaction quotient Q for the cell
$Z n (s) | Z n^{2 +} (0.01 M) | | A g^{\oplus} (1.25 M) | A g (s) i s$ :

156

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125

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1.25 \times 10^{- 2}

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64 \times 10^{- 3}

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Solution

The correct option is B $64 \times 10^{- 3}$
cell reaction :
$Z n (s) + 2 A g^{\oplus} (1.25 M) \to Z n^{2 +} (0.01 M) + 2 A g (s)$
$Q = \frac{[Z n^{2 +}]}{[A g^{\oplus}]} = \frac{0.01}{(1.25)^{2}} = 64 \times 10^{- 3}$

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Similar questions

Q

Z n (s) | Z n^{2 +} (0.01 M) ∥ A g^{+} (1.25 M) | A g (s)

(Q)

Z n (s) | Z n^{2 +} (0.01 M) | | A g^{+} (1.25 M) | A g (s)

The EMF of the cell

$Z n | Z n^{2 +} (0.01 M) | | F e^{2 +} (0.001 M) | F e$ at $298 K$ is $0.2905$ then the value of equilibrium constant for the cell reaction is :

Z n | Z n^{2 +} (0.01 M) | | F e^{2 +} (0.001 M) | F e

298 K

0.2905 V

△ G^{\circ}

Z n (s) + A g_{2} O (s) + H_{2} O (l) ⇌ Z n^{2 +} (a q) + 2 A g (s) + 2 O H^{-} (a q)

E_{A g^{+} / A g}^{\circ} = + 0.80 V

E_{Z n^{2 +} / Z N}^{\circ} = - 0.76 V

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