The value of the reaction quotient $Q$ , for the cell
$Z n (s) | Z n^{2 +} (0.01 M) ∥ A g^{+} (1.25 M) | A g (s)$ is_________.

156

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125

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1.25 \times 10^{- 2}

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6.4 \times 10^{- 3}

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Solution

The correct option is D $6.4 \times 10^{- 3}$
$Z n (s) \to Z n^{2 +} + 2 e^{-}$ (Anodic process)
$2 A g^{+} + 2 e^{-} \to 2 A g (s) - ---------------------- -$ (Cathodic process)
$Z n (s) + 2 A g^{+} ⇌ 2 A g (s) + Z n^{2 +} - ---------------------------------- -$
$Q = \frac{[Z n^{2 +}]}{[A g^{+}]^{2}} = \frac{0, 01}{(1.25)^{2}} = 6.4 \times 10^{- 3}$ .

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Similar questions

(Q)

Z n (s) | Z n^{2 +} (0.01 M) | | A g^{+} (1.25 M) | A g (s)

Z n (s) | Z n^{2 +} (0.01 M) | | A g^{\oplus} (1.25 M) | A g (s) i s

The cell representation of the given reactions is:

Zn(s) + 2Ag⁺ → Zn²⁺ + 2Ag(s)

A g (s) A g I O_{3} (s) | A g^{+} (x M), H I O_{3} (0.300 M) | ∣ ∣ Z n^{2 +} (0.175 M) ∣ ∣ Z n (s)

K_{S P} = 3.02 \times 10^{- 8}

A g I O_{3} (s)

K_{a} = 0.162

H I O_{3}, E^{\circ} (Z n^{2 +} / Z n) = - 0.76 V, E^{\circ} (A g / A g^{+} = - 0.8 V)

△ G^{\circ}

Z n (s) + A g_{2} O (s) + H_{2} O (l) ⇌ Z n^{2 +} (a q) + 2 A g (s) + 2 O H^{-} (a q)

E_{A g^{+} / A g}^{\circ} = + 0.80 V

E_{Z n^{2 +} / Z N}^{\circ} = - 0.76 V

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