The value of the sum of two vectors A- and B- with - as the angle between them is

The correct option is A √(A^2+B^2+2ABcosθ) As we know, #160;Resultant of two vectors A⃗ and B⃗ is #160; R=√(A^2+B^2+2ABcosθ) ...

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Vector Addition

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Question

The value of the sum of two vectors $\to A$ and $\to B$ with $θ$ as the angle between them is

\sqrt{A^{2} + B^{2} + 2 A B cos θ}

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\sqrt{A^{2} - B^{2} + 2 A B cos θ}

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\sqrt{A^{2} + B^{2} - 2 A B sin θ}

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\sqrt{A^{2} + B^{2} + 2 A B sin θ}

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\to A

\to B

\to A + \to B = \to C

A^{2} + B^{2} = C^{2}

θ

\to A

\to B

If $s i n θ = \frac{a^{2} - b^{2}}{a^{2} + b^{2}}$ , find the values of tan $θ, s e c θ$ and $c o s e c θ .$

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

θ

θ

θ

θ

a^{2} + b^{2} .

If sin $θ = \frac{a^{2} - b^{2}}{a^{2} + b^{2}}$ , find the values of all T-ratios of $θ$

sin

θ = \frac{a^{2} - b^{2}}{a^{2} + b^{2}}

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