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Question

The value of the summation i=12i12i+1 is

A
32
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B
43
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C
53
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D
3
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Solution

The correct option is A 32
Let S=i=12i12i+1
S=14+38+516+732+
4S=(1+32+54+78+)
Now clearly, the series is an AGP with a=1, d=2, r=12.
Hence, using the formula for the sum of infinite terms of AGP, we get
S=14⎜ ⎜ ⎜ ⎜ ⎜1112+212(112)2⎟ ⎟ ⎟ ⎟ ⎟
=14(2+4)=32

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