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Question

The value of θ satisfying sin7θ=sin4θsinθin0<θ<π2 are

A
π9,π4
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B
π3,π9
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C
π6,π4
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D
0,1
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Solution

The correct option is A π9,π4
sin7θ+sinθ=sin4θ

2sin4θ.cos3θ=sin4θ

sin4θ(2cos3θ1)=0

sin4θ=0,cos3θ=12

θ=π4,θ=π9

θ=π/4,π/9

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