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Byju's Answer

Standard XII

Chemistry

Gibbs Free Energy & Spontaneity

The value of ...

Question

The value of $△ G (k J m o l^{- 1})$ for the given cell is: (take $1 F = 96500 C m o l^{- 1})$

- 5.7

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5.7

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11.4

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- 11.4

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Solution

The correct option is A $- 11.4$
$△ G = - n F E$
$= - 2 \times 96500 \times 0.059$
$= - 11.4 k J / m o l$ .

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The value of △G(kJ mol−1) for the given cell is: (take 1F=96500 C mol−1)

The correct option is A −11.4△G=−nFE=−2×96500×0.059=−11.4 kJ/mol.

The value of $△ G (k J m o l^{- 1})$ for the given cell is: (take $1 F = 96500 C m o l^{- 1})$

The correct option is A $- 11.4$
$△ G = - n F E$
$= - 2 \times 96500 \times 0.059$
$= - 11.4 k J / m o l$ .