The value of universal gas constant is $8.3 J / m o l e / K$ , the mean kinetic energy of $32 g m$ of oxygen at $- 73^{o} C$ will be

480 J

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4980 J

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2490 J

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100 J

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Solution

The correct option is B $4980 J$
$R = 8.3 J / m o l e K$ , atomic weight of $n a s c e n t$ oxygen is $16$
so number of moles $n = \frac{32}{16} = 2$
Mean kinetic energy will be $K E = \frac{n F R T}{2}$
Where $F$ is degree of freedom which will be $3$ because $O$ is a mono-atomic molecule.
Temperature, $T = - 73 + 273 = 200 K$
So energy= $\frac{2 \times 3 \times 8.3 \times 200}{2} = 4980 J o u l e$

So, Option B is correct.

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Similar questions

The value of universal gas constant is 8.3 J/mole/K, the mean kinetic energy of 32 gm of oxygen at $- 73^{\circ} C$ will be

8.3 J / m o l e

K

- 736 \circ C

8.3 j o u l e m o l^{- 1} K^{- 1}

6 \times 10^{23}

327^{\circ} C

[R = 8.3 J / m o l - K]

14 g

32 g m

300 K ?

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