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Kirchhoff's Junction Law

The value of ...

Question

The value of $V_{0}$ in the following diagram is

A

4V

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B

6V

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C

8V

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D

10V

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Solution

The correct option is C 8V

$\frac{V_{A} - V_{0}}{10} = \frac{V_{0} - V_{B}}{20} + \frac{V_{0} - V_{C}}{30}$
$6 (10 - V_{0}) = 3 (V_{0} - 6) + 2 (V_{0} - 5)$
$60 - 6 V_{0} = 3 V_{0} - 18 + 2 V_{0} - 10$
$88 = 11 V_{0}$
$V_{0} = 8$

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