Question

The value of $V_0$ in the following diagram is

• A. 4V
• B. 6V
• C. 8V
• D. 10V

Answer 1

The correct option is C 8V



$\frac{V_A-V_0}{10}=\frac{V_0-V_B}{20}+\frac{V_0-V_C}{30}$
$6(10-V_0)=3(V_0-6)+2(V_0-5)$
$60-6V_0=3V_0-18+2V_0-10$
$88=11V_0$
$V_0=8$